Optimal. Leaf size=212 \[ \frac {\left (2 b^2 B-A b c-6 a B c\right ) x^2}{2 c^2 \left (b^2-4 a c\right )}-\frac {x^4 \left (a (b B-2 A c)+\left (b^2 B-A b c-2 a B c\right ) x^2\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}-\frac {\left (2 b^4 B-A b^3 c-12 a b^2 B c+6 a A b c^2+12 a^2 B c^2\right ) \tanh ^{-1}\left (\frac {b+2 c x^2}{\sqrt {b^2-4 a c}}\right )}{2 c^3 \left (b^2-4 a c\right )^{3/2}}-\frac {(2 b B-A c) \log \left (a+b x^2+c x^4\right )}{4 c^3} \]
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Rubi [A]
time = 0.25, antiderivative size = 212, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 7, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.280, Rules used = {1265, 832, 787,
648, 632, 212, 642} \begin {gather*} -\frac {\left (12 a^2 B c^2+6 a A b c^2-12 a b^2 B c-A b^3 c+2 b^4 B\right ) \tanh ^{-1}\left (\frac {b+2 c x^2}{\sqrt {b^2-4 a c}}\right )}{2 c^3 \left (b^2-4 a c\right )^{3/2}}+\frac {x^2 \left (-6 a B c-A b c+2 b^2 B\right )}{2 c^2 \left (b^2-4 a c\right )}-\frac {x^4 \left (x^2 \left (-2 a B c-A b c+b^2 B\right )+a (b B-2 A c)\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}-\frac {(2 b B-A c) \log \left (a+b x^2+c x^4\right )}{4 c^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 632
Rule 642
Rule 648
Rule 787
Rule 832
Rule 1265
Rubi steps
\begin {align*} \int \frac {x^7 \left (A+B x^2\right )}{\left (a+b x^2+c x^4\right )^2} \, dx &=\frac {1}{2} \text {Subst}\left (\int \frac {x^3 (A+B x)}{\left (a+b x+c x^2\right )^2} \, dx,x,x^2\right )\\ &=-\frac {x^4 \left (a (b B-2 A c)+\left (b^2 B-A b c-2 a B c\right ) x^2\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}+\frac {\text {Subst}\left (\int \frac {x \left (2 a (b B-2 A c)+\left (2 b^2 B-A b c-6 a B c\right ) x\right )}{a+b x+c x^2} \, dx,x,x^2\right )}{2 c \left (b^2-4 a c\right )}\\ &=\frac {\left (2 b^2 B-A b c-6 a B c\right ) x^2}{2 c^2 \left (b^2-4 a c\right )}-\frac {x^4 \left (a (b B-2 A c)+\left (b^2 B-A b c-2 a B c\right ) x^2\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}+\frac {\text {Subst}\left (\int \frac {-a \left (2 b^2 B-A b c-6 a B c\right )+\left (2 a c (b B-2 A c)-b \left (2 b^2 B-A b c-6 a B c\right )\right ) x}{a+b x+c x^2} \, dx,x,x^2\right )}{2 c^2 \left (b^2-4 a c\right )}\\ &=\frac {\left (2 b^2 B-A b c-6 a B c\right ) x^2}{2 c^2 \left (b^2-4 a c\right )}-\frac {x^4 \left (a (b B-2 A c)+\left (b^2 B-A b c-2 a B c\right ) x^2\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}-\frac {(2 b B-A c) \text {Subst}\left (\int \frac {b+2 c x}{a+b x+c x^2} \, dx,x,x^2\right )}{4 c^3}+\frac {\left (2 b^4 B-A b^3 c-12 a b^2 B c+6 a A b c^2+12 a^2 B c^2\right ) \text {Subst}\left (\int \frac {1}{a+b x+c x^2} \, dx,x,x^2\right )}{4 c^3 \left (b^2-4 a c\right )}\\ &=\frac {\left (2 b^2 B-A b c-6 a B c\right ) x^2}{2 c^2 \left (b^2-4 a c\right )}-\frac {x^4 \left (a (b B-2 A c)+\left (b^2 B-A b c-2 a B c\right ) x^2\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}-\frac {(2 b B-A c) \log \left (a+b x^2+c x^4\right )}{4 c^3}-\frac {\left (2 b^4 B-A b^3 c-12 a b^2 B c+6 a A b c^2+12 a^2 B c^2\right ) \text {Subst}\left (\int \frac {1}{b^2-4 a c-x^2} \, dx,x,b+2 c x^2\right )}{2 c^3 \left (b^2-4 a c\right )}\\ &=\frac {\left (2 b^2 B-A b c-6 a B c\right ) x^2}{2 c^2 \left (b^2-4 a c\right )}-\frac {x^4 \left (a (b B-2 A c)+\left (b^2 B-A b c-2 a B c\right ) x^2\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}-\frac {\left (2 b^4 B-A b^3 c-12 a b^2 B c+6 a A b c^2+12 a^2 B c^2\right ) \tanh ^{-1}\left (\frac {b+2 c x^2}{\sqrt {b^2-4 a c}}\right )}{2 c^3 \left (b^2-4 a c\right )^{3/2}}-\frac {(2 b B-A c) \log \left (a+b x^2+c x^4\right )}{4 c^3}\\ \end {align*}
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Mathematica [A]
time = 0.19, size = 208, normalized size = 0.98 \begin {gather*} \frac {2 B c x^2-\frac {2 \left (b^3 (b B-A c) x^2+a^2 c \left (-3 b B+2 c \left (A+B x^2\right )\right )+a b \left (b^2 B+3 A c^2 x^2-b c \left (A+4 B x^2\right )\right )\right )}{\left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}-\frac {2 \left (2 b^4 B-A b^3 c-12 a b^2 B c+6 a A b c^2+12 a^2 B c^2\right ) \tan ^{-1}\left (\frac {b+2 c x^2}{\sqrt {-b^2+4 a c}}\right )}{\left (-b^2+4 a c\right )^{3/2}}+(-2 b B+A c) \log \left (a+b x^2+c x^4\right )}{4 c^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.10, size = 282, normalized size = 1.33
method | result | size |
default | \(\frac {B \,x^{2}}{2 c^{2}}+\frac {\frac {\frac {\left (3 A a b \,c^{2}-A \,b^{3} c +2 a^{2} B \,c^{2}-4 a \,b^{2} B c +b^{4} B \right ) x^{2}}{c \left (4 a c -b^{2}\right )}+\frac {a \left (2 c^{2} a A -A \,b^{2} c -3 a b B c +b^{3} B \right )}{c \left (4 a c -b^{2}\right )}}{c \,x^{4}+b \,x^{2}+a}+\frac {\frac {\left (4 c^{2} a A -A \,b^{2} c -8 a b B c +2 b^{3} B \right ) \ln \left (c \,x^{4}+b \,x^{2}+a \right )}{2 c}+\frac {2 \left (-A a b c -6 a^{2} c B +2 B a \,b^{2}-\frac {\left (4 c^{2} a A -A \,b^{2} c -8 a b B c +2 b^{3} B \right ) b}{2 c}\right ) \arctan \left (\frac {2 c \,x^{2}+b}{\sqrt {4 a c -b^{2}}}\right )}{\sqrt {4 a c -b^{2}}}}{4 a c -b^{2}}}{2 c^{2}}\) | \(282\) |
risch | \(\text {Expression too large to display}\) | \(3097\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 650 vs.
\(2 (200) = 400\).
time = 0.44, size = 1323, normalized size = 6.24 \begin {gather*} \left [-\frac {2 \, B a b^{5} - 16 \, A a^{3} c^{3} - 2 \, {\left (B b^{4} c^{2} - 8 \, B a b^{2} c^{3} + 16 \, B a^{2} c^{4}\right )} x^{6} - 2 \, {\left (B b^{5} c - 8 \, B a b^{3} c^{2} + 16 \, B a^{2} b c^{3}\right )} x^{4} + 12 \, {\left (2 \, B a^{3} b + A a^{2} b^{2}\right )} c^{2} + 2 \, {\left (B b^{6} - 12 \, {\left (2 \, B a^{3} + A a^{2} b\right )} c^{3} + {\left (26 \, B a^{2} b^{2} + 7 \, A a b^{3}\right )} c^{2} - {\left (9 \, B a b^{4} + A b^{5}\right )} c\right )} x^{2} + {\left (2 \, B a b^{4} + {\left (2 \, B b^{4} c + 6 \, {\left (2 \, B a^{2} + A a b\right )} c^{3} - {\left (12 \, B a b^{2} + A b^{3}\right )} c^{2}\right )} x^{4} + 6 \, {\left (2 \, B a^{3} + A a^{2} b\right )} c^{2} + {\left (2 \, B b^{5} + 6 \, {\left (2 \, B a^{2} b + A a b^{2}\right )} c^{2} - {\left (12 \, B a b^{3} + A b^{4}\right )} c\right )} x^{2} - {\left (12 \, B a^{2} b^{2} + A a b^{3}\right )} c\right )} \sqrt {b^{2} - 4 \, a c} \log \left (\frac {2 \, c^{2} x^{4} + 2 \, b c x^{2} + b^{2} - 2 \, a c + {\left (2 \, c x^{2} + b\right )} \sqrt {b^{2} - 4 \, a c}}{c x^{4} + b x^{2} + a}\right ) - 2 \, {\left (7 \, B a^{2} b^{3} + A a b^{4}\right )} c + {\left (2 \, B a b^{5} - 16 \, A a^{3} c^{3} + {\left (2 \, B b^{5} c - 16 \, A a^{2} c^{4} + 8 \, {\left (4 \, B a^{2} b + A a b^{2}\right )} c^{3} - {\left (16 \, B a b^{3} + A b^{4}\right )} c^{2}\right )} x^{4} + 8 \, {\left (4 \, B a^{3} b + A a^{2} b^{2}\right )} c^{2} + {\left (2 \, B b^{6} - 16 \, A a^{2} b c^{3} + 8 \, {\left (4 \, B a^{2} b^{2} + A a b^{3}\right )} c^{2} - {\left (16 \, B a b^{4} + A b^{5}\right )} c\right )} x^{2} - {\left (16 \, B a^{2} b^{3} + A a b^{4}\right )} c\right )} \log \left (c x^{4} + b x^{2} + a\right )}{4 \, {\left (a b^{4} c^{3} - 8 \, a^{2} b^{2} c^{4} + 16 \, a^{3} c^{5} + {\left (b^{4} c^{4} - 8 \, a b^{2} c^{5} + 16 \, a^{2} c^{6}\right )} x^{4} + {\left (b^{5} c^{3} - 8 \, a b^{3} c^{4} + 16 \, a^{2} b c^{5}\right )} x^{2}\right )}}, -\frac {2 \, B a b^{5} - 16 \, A a^{3} c^{3} - 2 \, {\left (B b^{4} c^{2} - 8 \, B a b^{2} c^{3} + 16 \, B a^{2} c^{4}\right )} x^{6} - 2 \, {\left (B b^{5} c - 8 \, B a b^{3} c^{2} + 16 \, B a^{2} b c^{3}\right )} x^{4} + 12 \, {\left (2 \, B a^{3} b + A a^{2} b^{2}\right )} c^{2} + 2 \, {\left (B b^{6} - 12 \, {\left (2 \, B a^{3} + A a^{2} b\right )} c^{3} + {\left (26 \, B a^{2} b^{2} + 7 \, A a b^{3}\right )} c^{2} - {\left (9 \, B a b^{4} + A b^{5}\right )} c\right )} x^{2} + 2 \, {\left (2 \, B a b^{4} + {\left (2 \, B b^{4} c + 6 \, {\left (2 \, B a^{2} + A a b\right )} c^{3} - {\left (12 \, B a b^{2} + A b^{3}\right )} c^{2}\right )} x^{4} + 6 \, {\left (2 \, B a^{3} + A a^{2} b\right )} c^{2} + {\left (2 \, B b^{5} + 6 \, {\left (2 \, B a^{2} b + A a b^{2}\right )} c^{2} - {\left (12 \, B a b^{3} + A b^{4}\right )} c\right )} x^{2} - {\left (12 \, B a^{2} b^{2} + A a b^{3}\right )} c\right )} \sqrt {-b^{2} + 4 \, a c} \arctan \left (-\frac {{\left (2 \, c x^{2} + b\right )} \sqrt {-b^{2} + 4 \, a c}}{b^{2} - 4 \, a c}\right ) - 2 \, {\left (7 \, B a^{2} b^{3} + A a b^{4}\right )} c + {\left (2 \, B a b^{5} - 16 \, A a^{3} c^{3} + {\left (2 \, B b^{5} c - 16 \, A a^{2} c^{4} + 8 \, {\left (4 \, B a^{2} b + A a b^{2}\right )} c^{3} - {\left (16 \, B a b^{3} + A b^{4}\right )} c^{2}\right )} x^{4} + 8 \, {\left (4 \, B a^{3} b + A a^{2} b^{2}\right )} c^{2} + {\left (2 \, B b^{6} - 16 \, A a^{2} b c^{3} + 8 \, {\left (4 \, B a^{2} b^{2} + A a b^{3}\right )} c^{2} - {\left (16 \, B a b^{4} + A b^{5}\right )} c\right )} x^{2} - {\left (16 \, B a^{2} b^{3} + A a b^{4}\right )} c\right )} \log \left (c x^{4} + b x^{2} + a\right )}{4 \, {\left (a b^{4} c^{3} - 8 \, a^{2} b^{2} c^{4} + 16 \, a^{3} c^{5} + {\left (b^{4} c^{4} - 8 \, a b^{2} c^{5} + 16 \, a^{2} c^{6}\right )} x^{4} + {\left (b^{5} c^{3} - 8 \, a b^{3} c^{4} + 16 \, a^{2} b c^{5}\right )} x^{2}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 4.88, size = 239, normalized size = 1.13 \begin {gather*} \frac {B x^{2}}{2 \, c^{2}} + \frac {{\left (2 \, B b^{4} - 12 \, B a b^{2} c - A b^{3} c + 12 \, B a^{2} c^{2} + 6 \, A a b c^{2}\right )} \arctan \left (\frac {2 \, c x^{2} + b}{\sqrt {-b^{2} + 4 \, a c}}\right )}{2 \, {\left (b^{2} c^{3} - 4 \, a c^{4}\right )} \sqrt {-b^{2} + 4 \, a c}} + \frac {2 \, B b^{3} x^{4} - 8 \, B a b c x^{4} - A b^{2} c x^{4} + 4 \, A a c^{2} x^{4} + A b^{3} x^{2} - 4 \, B a^{2} c x^{2} - 2 \, A a b c x^{2} - 2 \, B a^{2} b + A a b^{2}}{4 \, {\left (c x^{4} + b x^{2} + a\right )} {\left (b^{2} c^{2} - 4 \, a c^{3}\right )}} - \frac {{\left (2 \, B b - A c\right )} \log \left (c x^{4} + b x^{2} + a\right )}{4 \, c^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.83, size = 2282, normalized size = 10.76 \begin {gather*} \frac {\frac {a\,\left (B\,b^3-A\,b^2\,c-3\,B\,a\,b\,c+2\,A\,a\,c^2\right )}{2\,c\,\left (4\,a\,c-b^2\right )}+\frac {x^2\,\left (2\,B\,a^2\,c^2-4\,B\,a\,b^2\,c+3\,A\,a\,b\,c^2+B\,b^4-A\,b^3\,c\right )}{2\,c\,\left (4\,a\,c-b^2\right )}}{c^3\,x^4+b\,c^2\,x^2+a\,c^2}+\frac {B\,x^2}{2\,c^2}+\frac {\ln \left (c\,x^4+b\,x^2+a\right )\,\left (-256\,B\,a^3\,b\,c^3+128\,A\,a^3\,c^4+192\,B\,a^2\,b^3\,c^2-96\,A\,a^2\,b^2\,c^3-48\,B\,a\,b^5\,c+24\,A\,a\,b^4\,c^2+4\,B\,b^7-2\,A\,b^6\,c\right )}{2\,\left (256\,a^3\,c^6-192\,a^2\,b^2\,c^5+48\,a\,b^4\,c^4-4\,b^6\,c^3\right )}-\frac {\mathrm {atan}\left (\frac {\left (8\,a\,c^5\,{\left (4\,a\,c-b^2\right )}^3-2\,b^2\,c^4\,{\left (4\,a\,c-b^2\right )}^3\right )\,\left (x^2\,\left (\frac {\frac {\left (\frac {24\,B\,a^2\,c^5-56\,B\,a\,b^2\,c^4+28\,A\,a\,b\,c^5+12\,B\,b^4\,c^3-6\,A\,b^3\,c^4}{4\,a\,c^5-b^2\,c^4}+\frac {\left (8\,b^3\,c^6-32\,a\,b\,c^7\right )\,\left (-256\,B\,a^3\,b\,c^3+128\,A\,a^3\,c^4+192\,B\,a^2\,b^3\,c^2-96\,A\,a^2\,b^2\,c^3-48\,B\,a\,b^5\,c+24\,A\,a\,b^4\,c^2+4\,B\,b^7-2\,A\,b^6\,c\right )}{2\,\left (4\,a\,c^5-b^2\,c^4\right )\,\left (256\,a^3\,c^6-192\,a^2\,b^2\,c^5+48\,a\,b^4\,c^4-4\,b^6\,c^3\right )}\right )\,\left (12\,B\,a^2\,c^2-12\,B\,a\,b^2\,c+6\,A\,a\,b\,c^2+2\,B\,b^4-A\,b^3\,c\right )}{8\,c^3\,{\left (4\,a\,c-b^2\right )}^{3/2}}+\frac {\left (8\,b^3\,c^6-32\,a\,b\,c^7\right )\,\left (12\,B\,a^2\,c^2-12\,B\,a\,b^2\,c+6\,A\,a\,b\,c^2+2\,B\,b^4-A\,b^3\,c\right )\,\left (-256\,B\,a^3\,b\,c^3+128\,A\,a^3\,c^4+192\,B\,a^2\,b^3\,c^2-96\,A\,a^2\,b^2\,c^3-48\,B\,a\,b^5\,c+24\,A\,a\,b^4\,c^2+4\,B\,b^7-2\,A\,b^6\,c\right )}{16\,c^3\,{\left (4\,a\,c-b^2\right )}^{3/2}\,\left (4\,a\,c^5-b^2\,c^4\right )\,\left (256\,a^3\,c^6-192\,a^2\,b^2\,c^5+48\,a\,b^4\,c^4-4\,b^6\,c^3\right )}}{a\,\left (4\,a\,c-b^2\right )}+\frac {b\,\left (\frac {-5\,A^2\,a\,b\,c^3+A^2\,b^3\,c^2-6\,A\,B\,a^2\,c^3+20\,A\,B\,a\,b^2\,c^2-4\,A\,B\,b^4\,c+12\,B^2\,a^2\,b\,c^2-20\,B^2\,a\,b^3\,c+4\,B^2\,b^5}{4\,a\,c^5-b^2\,c^4}+\frac {\left (\frac {24\,B\,a^2\,c^5-56\,B\,a\,b^2\,c^4+28\,A\,a\,b\,c^5+12\,B\,b^4\,c^3-6\,A\,b^3\,c^4}{4\,a\,c^5-b^2\,c^4}+\frac {\left (8\,b^3\,c^6-32\,a\,b\,c^7\right )\,\left (-256\,B\,a^3\,b\,c^3+128\,A\,a^3\,c^4+192\,B\,a^2\,b^3\,c^2-96\,A\,a^2\,b^2\,c^3-48\,B\,a\,b^5\,c+24\,A\,a\,b^4\,c^2+4\,B\,b^7-2\,A\,b^6\,c\right )}{2\,\left (4\,a\,c^5-b^2\,c^4\right )\,\left (256\,a^3\,c^6-192\,a^2\,b^2\,c^5+48\,a\,b^4\,c^4-4\,b^6\,c^3\right )}\right )\,\left (-256\,B\,a^3\,b\,c^3+128\,A\,a^3\,c^4+192\,B\,a^2\,b^3\,c^2-96\,A\,a^2\,b^2\,c^3-48\,B\,a\,b^5\,c+24\,A\,a\,b^4\,c^2+4\,B\,b^7-2\,A\,b^6\,c\right )}{2\,\left (256\,a^3\,c^6-192\,a^2\,b^2\,c^5+48\,a\,b^4\,c^4-4\,b^6\,c^3\right )}-\frac {\left (\frac {b^3\,c^6}{2}-2\,a\,b\,c^7\right )\,{\left (12\,B\,a^2\,c^2-12\,B\,a\,b^2\,c+6\,A\,a\,b\,c^2+2\,B\,b^4-A\,b^3\,c\right )}^2}{c^6\,{\left (4\,a\,c-b^2\right )}^3\,\left (4\,a\,c^5-b^2\,c^4\right )}\right )}{2\,a\,{\left (4\,a\,c-b^2\right )}^{3/2}}\right )+\frac {\frac {\left (\frac {8\,A\,a\,c^4-16\,B\,a\,b\,c^3}{c^4}-\frac {8\,a\,c^2\,\left (-256\,B\,a^3\,b\,c^3+128\,A\,a^3\,c^4+192\,B\,a^2\,b^3\,c^2-96\,A\,a^2\,b^2\,c^3-48\,B\,a\,b^5\,c+24\,A\,a\,b^4\,c^2+4\,B\,b^7-2\,A\,b^6\,c\right )}{256\,a^3\,c^6-192\,a^2\,b^2\,c^5+48\,a\,b^4\,c^4-4\,b^6\,c^3}\right )\,\left (12\,B\,a^2\,c^2-12\,B\,a\,b^2\,c+6\,A\,a\,b\,c^2+2\,B\,b^4-A\,b^3\,c\right )}{8\,c^3\,{\left (4\,a\,c-b^2\right )}^{3/2}}-\frac {a\,\left (12\,B\,a^2\,c^2-12\,B\,a\,b^2\,c+6\,A\,a\,b\,c^2+2\,B\,b^4-A\,b^3\,c\right )\,\left (-256\,B\,a^3\,b\,c^3+128\,A\,a^3\,c^4+192\,B\,a^2\,b^3\,c^2-96\,A\,a^2\,b^2\,c^3-48\,B\,a\,b^5\,c+24\,A\,a\,b^4\,c^2+4\,B\,b^7-2\,A\,b^6\,c\right )}{c\,{\left (4\,a\,c-b^2\right )}^{3/2}\,\left (256\,a^3\,c^6-192\,a^2\,b^2\,c^5+48\,a\,b^4\,c^4-4\,b^6\,c^3\right )}}{a\,\left (4\,a\,c-b^2\right )}+\frac {b\,\left (\frac {\left (\frac {8\,A\,a\,c^4-16\,B\,a\,b\,c^3}{c^4}-\frac {8\,a\,c^2\,\left (-256\,B\,a^3\,b\,c^3+128\,A\,a^3\,c^4+192\,B\,a^2\,b^3\,c^2-96\,A\,a^2\,b^2\,c^3-48\,B\,a\,b^5\,c+24\,A\,a\,b^4\,c^2+4\,B\,b^7-2\,A\,b^6\,c\right )}{256\,a^3\,c^6-192\,a^2\,b^2\,c^5+48\,a\,b^4\,c^4-4\,b^6\,c^3}\right )\,\left (-256\,B\,a^3\,b\,c^3+128\,A\,a^3\,c^4+192\,B\,a^2\,b^3\,c^2-96\,A\,a^2\,b^2\,c^3-48\,B\,a\,b^5\,c+24\,A\,a\,b^4\,c^2+4\,B\,b^7-2\,A\,b^6\,c\right )}{2\,\left (256\,a^3\,c^6-192\,a^2\,b^2\,c^5+48\,a\,b^4\,c^4-4\,b^6\,c^3\right )}-\frac {a\,A^2\,c^2-4\,a\,A\,B\,b\,c+4\,a\,B^2\,b^2}{c^4}+\frac {a\,{\left (12\,B\,a^2\,c^2-12\,B\,a\,b^2\,c+6\,A\,a\,b\,c^2+2\,B\,b^4-A\,b^3\,c\right )}^2}{c^4\,{\left (4\,a\,c-b^2\right )}^3}\right )}{2\,a\,{\left (4\,a\,c-b^2\right )}^{3/2}}\right )}{36\,A^2\,a^2\,b^2\,c^4-12\,A^2\,a\,b^4\,c^3+A^2\,b^6\,c^2+144\,A\,B\,a^3\,b\,c^4-168\,A\,B\,a^2\,b^3\,c^3+48\,A\,B\,a\,b^5\,c^2-4\,A\,B\,b^7\,c+144\,B^2\,a^4\,c^4-288\,B^2\,a^3\,b^2\,c^3+192\,B^2\,a^2\,b^4\,c^2-48\,B^2\,a\,b^6\,c+4\,B^2\,b^8}\right )\,\left (12\,B\,a^2\,c^2-12\,B\,a\,b^2\,c+6\,A\,a\,b\,c^2+2\,B\,b^4-A\,b^3\,c\right )}{2\,c^3\,{\left (4\,a\,c-b^2\right )}^{3/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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